JNU Field Investigator Recruitment 2025 - Offline Apply for 2 Posts

Jawaharlal Nehru University (JNU)
Posted:

Overview

Jawaharlal Nehru University (JNU) invites applications for 2 Field Investigator posts. This is an offline recruitment with the last date to apply on 14 November 2025. The position offers a remuneration of ₹20,000 per month and requires a Master’s degree (M.A.).

Total Vacancies

2

Age Limit

TBA

Eligibility

Educational Qualifications

  • Postgraduate degree in any Social Science discipline with at least 55% marks.
  • Preference will be given to candidates with field research experience in Tribal Literature or Tribal Studies.

Important Dates

Application Start

TBA

Application End

14/11/25

Date Details

Important Dates

  • Last Date for Apply: 14-11-2025
  • Updated information: November 6, 2025 (11:44 AM)

Application Fees

Application Fee

  • No fees information provided in the post. If a fee structure exists, it should be added here.

How to Apply

Additional Instructions

  • This post is for Offline submission only. Candidates should prepare and send their CV along with a brief statement of interest to the provided address by the last date.
  • Shortlisting will be based on qualifications and suitability for the project.
  • Ensure you refer to the official notification for any updates or changes to the process.

Frequently Asked Questions

Which body conducts the "JNU Field Investigator Recruitment 2025 - Offline Apply for 2 Posts"?

The "JNU Field Investigator Recruitment 2025 - Offline Apply for 2 Posts" is conducted by the Jawaharlal Nehru University (JNU).

How many vacancies are there for "JNU Field Investigator Recruitment 2025 - Offline Apply for 2 Posts"?

There are a total of 2 vacancies available for "JNU Field Investigator Recruitment 2025 - Offline Apply for 2 Posts".

What is the last date to apply for "JNU Field Investigator Recruitment 2025 - Offline Apply for 2 Posts"?

The deadline to apply for "JNU Field Investigator Recruitment 2025 - Offline Apply for 2 Posts" is 14/11/25.

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